sin^2x(1+cot^2x)=1

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Solution for sin^2x(1+cot^2x)=1 equation:


Simplifying
sin2x(1 + cot2x) = 1
(1 * in2sx + cot2x * in2sx) = 1

Reorder the terms:
(cin2ost2x2 + 1in2sx) = 1
(cin2ost2x2 + 1in2sx) = 1

Solving
cin2ost2x2 + 1in2sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
cin2ost2x2 + 1in2sx + -1in2sx = 1 + -1in2sx

Combine like terms: 1in2sx + -1in2sx = 0
cin2ost2x2 + 0 = 1 + -1in2sx
cin2ost2x2 = 1 + -1in2sx

Divide each side by 'in2ost2x2'.
c = i-1n-2o-1s-1t-2x-2 + -1o-1t-2x-1

Simplifying
c = i-1n-2o-1s-1t-2x-2 + -1o-1t-2x-1

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